解决 船与运输问题

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drop table v1;
create table v1( 
name varchar(10),--人名,addres varchar(10)  --去哪里,); 
insert into v1 values('my1','上海'); 
insert into v1 values('my2','北京'); 
insert into v1 values('my3','上海'); 
insert into v1 values('my4','江西'); 
insert into v1 values('my5','上海'); 
select * from v1;
drop table v2;
create table v2( 
shipname varchar(10),--船名,addres varchar(10)  --去哪里
); 
insert into v2 values('ship1','上海'); 
insert into v2 values('ship2','北京'); 
insert into v2 values('ship3','上海'); 
insert into v2 values('ship4','四川'); 
select * from v2;

select v1.name,v1.addres,ROW_NUMBER() OVER(PARTITION BY v1.addres ORDER BY v1.addres DESC) AS 'RowNumber'
 from v1 order by v1.name;
 select v2.addres,v2.shipname,ROW_NUMBER() OVER(PARTITION BY v2.addres ORDER BY v2.addres DESC) AS 'RowNumber'
 from v2  order by v2.addres;
 
 select x.name,x.addres,y.shipname  from (select v1.name,ROW_NUMBER() OVER(PARTITION BY v1.addres ORDER BY v1.addres DESC) AS 'RowNumber'
 from v1) x left join (select v2.addres,ROW_NUMBER() OVER(PARTITION BY v2.addres ORDER BY v2.addres DESC) AS 'RowNumber'
 from v2) y on x.addres =y.addres and x.RowNumber=y.RowNumber

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